Optimal. Leaf size=257 \[ -\frac{(a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2} (B d-A e)}{4 e (d+e x)^4 (b d-a e)}+\frac{3 b^2 B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}{e^5 (a+b x) (d+e x)}-\frac{3 b B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{2 e^5 (a+b x) (d+e x)^2}+\frac{B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{3 e^5 (a+b x) (d+e x)^3}+\frac{b^3 B \sqrt{a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^5 (a+b x)} \]
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Rubi [A] time = 0.179016, antiderivative size = 257, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 3, integrand size = 33, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.091, Rules used = {770, 78, 43} \[ -\frac{(a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2} (B d-A e)}{4 e (d+e x)^4 (b d-a e)}+\frac{3 b^2 B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)}{e^5 (a+b x) (d+e x)}-\frac{3 b B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{2 e^5 (a+b x) (d+e x)^2}+\frac{B \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3}{3 e^5 (a+b x) (d+e x)^3}+\frac{b^3 B \sqrt{a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^5 (a+b x)} \]
Antiderivative was successfully verified.
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Rule 770
Rule 78
Rule 43
Rubi steps
\begin{align*} \int \frac{(A+B x) \left (a^2+2 a b x+b^2 x^2\right )^{3/2}}{(d+e x)^5} \, dx &=\frac{\sqrt{a^2+2 a b x+b^2 x^2} \int \frac{\left (a b+b^2 x\right )^3 (A+B x)}{(d+e x)^5} \, dx}{b^2 \left (a b+b^2 x\right )}\\ &=-\frac{(B d-A e) (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}{4 e (b d-a e) (d+e x)^4}+\frac{\left (B \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \frac{\left (a b+b^2 x\right )^3}{(d+e x)^4} \, dx}{b^2 e \left (a b+b^2 x\right )}\\ &=-\frac{(B d-A e) (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}{4 e (b d-a e) (d+e x)^4}+\frac{\left (B \sqrt{a^2+2 a b x+b^2 x^2}\right ) \int \left (-\frac{b^3 (b d-a e)^3}{e^3 (d+e x)^4}+\frac{3 b^4 (b d-a e)^2}{e^3 (d+e x)^3}-\frac{3 b^5 (b d-a e)}{e^3 (d+e x)^2}+\frac{b^6}{e^3 (d+e x)}\right ) \, dx}{b^2 e \left (a b+b^2 x\right )}\\ &=-\frac{(B d-A e) (a+b x)^3 \sqrt{a^2+2 a b x+b^2 x^2}}{4 e (b d-a e) (d+e x)^4}+\frac{B (b d-a e)^3 \sqrt{a^2+2 a b x+b^2 x^2}}{3 e^5 (a+b x) (d+e x)^3}-\frac{3 b B (b d-a e)^2 \sqrt{a^2+2 a b x+b^2 x^2}}{2 e^5 (a+b x) (d+e x)^2}+\frac{3 b^2 B (b d-a e) \sqrt{a^2+2 a b x+b^2 x^2}}{e^5 (a+b x) (d+e x)}+\frac{b^3 B \sqrt{a^2+2 a b x+b^2 x^2} \log (d+e x)}{e^5 (a+b x)}\\ \end{align*}
Mathematica [A] time = 0.157588, size = 240, normalized size = 0.93 \[ -\frac{\sqrt{(a+b x)^2} \left (3 a^2 b e^2 \left (A e (d+4 e x)+B \left (d^2+4 d e x+6 e^2 x^2\right )\right )+a^3 e^3 (3 A e+B (d+4 e x))+3 a b^2 e \left (A e \left (d^2+4 d e x+6 e^2 x^2\right )+3 B \left (4 d^2 e x+d^3+6 d e^2 x^2+4 e^3 x^3\right )\right )+b^3 \left (3 A e \left (4 d^2 e x+d^3+6 d e^2 x^2+4 e^3 x^3\right )-B d \left (88 d^2 e x+25 d^3+108 d e^2 x^2+48 e^3 x^3\right )\right )-12 b^3 B (d+e x)^4 \log (d+e x)\right )}{12 e^5 (a+b x) (d+e x)^4} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.014, size = 394, normalized size = 1.5 \begin{align*} -{\frac{54\,B{x}^{2}a{b}^{2}d{e}^{3}-88\,Bx{b}^{3}{d}^{3}e+12\,Ax{b}^{3}{d}^{2}{e}^{2}+12\,Ax{a}^{2}b{e}^{4}-108\,B{x}^{2}{b}^{3}{d}^{2}{e}^{2}+18\,B{x}^{2}{a}^{2}b{e}^{4}-48\,B{x}^{3}{b}^{3}d{e}^{3}+18\,A{x}^{2}a{b}^{2}{e}^{4}+18\,A{x}^{2}{b}^{3}d{e}^{3}+36\,B{x}^{3}a{b}^{2}{e}^{4}+3\,Ad{e}^{3}{a}^{2}b+3\,A{a}^{3}{e}^{4}-25\,B{b}^{3}{d}^{4}+9\,Ba{b}^{2}{d}^{3}e+3\,B{a}^{2}b{d}^{2}{e}^{2}+3\,Aa{b}^{2}{d}^{2}{e}^{2}-72\,B\ln \left ( ex+d \right ){x}^{2}{b}^{3}{d}^{2}{e}^{2}-48\,B\ln \left ( ex+d \right ) x{b}^{3}{d}^{3}e-48\,B\ln \left ( ex+d \right ){x}^{3}{b}^{3}d{e}^{3}+12\,Bx{a}^{2}bd{e}^{3}+36\,Bxa{b}^{2}{d}^{2}{e}^{2}+12\,Axa{b}^{2}d{e}^{3}+12\,A{x}^{3}{b}^{3}{e}^{4}-12\,B\ln \left ( ex+d \right ){b}^{3}{d}^{4}+4\,Bx{a}^{3}{e}^{4}+Bd{e}^{3}{a}^{3}+3\,A{b}^{3}{d}^{3}e-12\,B\ln \left ( ex+d \right ){x}^{4}{b}^{3}{e}^{4}}{12\, \left ( bx+a \right ) ^{3}{e}^{5} \left ( ex+d \right ) ^{4}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{3}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.81631, size = 726, normalized size = 2.82 \begin{align*} \frac{25 \, B b^{3} d^{4} - 3 \, A a^{3} e^{4} - 3 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d^{3} e - 3 \,{\left (B a^{2} b + A a b^{2}\right )} d^{2} e^{2} -{\left (B a^{3} + 3 \, A a^{2} b\right )} d e^{3} + 12 \,{\left (4 \, B b^{3} d e^{3} -{\left (3 \, B a b^{2} + A b^{3}\right )} e^{4}\right )} x^{3} + 18 \,{\left (6 \, B b^{3} d^{2} e^{2} -{\left (3 \, B a b^{2} + A b^{3}\right )} d e^{3} -{\left (B a^{2} b + A a b^{2}\right )} e^{4}\right )} x^{2} + 4 \,{\left (22 \, B b^{3} d^{3} e - 3 \,{\left (3 \, B a b^{2} + A b^{3}\right )} d^{2} e^{2} - 3 \,{\left (B a^{2} b + A a b^{2}\right )} d e^{3} -{\left (B a^{3} + 3 \, A a^{2} b\right )} e^{4}\right )} x + 12 \,{\left (B b^{3} e^{4} x^{4} + 4 \, B b^{3} d e^{3} x^{3} + 6 \, B b^{3} d^{2} e^{2} x^{2} + 4 \, B b^{3} d^{3} e x + B b^{3} d^{4}\right )} \log \left (e x + d\right )}{12 \,{\left (e^{9} x^{4} + 4 \, d e^{8} x^{3} + 6 \, d^{2} e^{7} x^{2} + 4 \, d^{3} e^{6} x + d^{4} e^{5}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.15777, size = 566, normalized size = 2.2 \begin{align*} B b^{3} e^{\left (-5\right )} \log \left ({\left | x e + d \right |}\right ) \mathrm{sgn}\left (b x + a\right ) + \frac{{\left (12 \,{\left (4 \, B b^{3} d e^{2} \mathrm{sgn}\left (b x + a\right ) - 3 \, B a b^{2} e^{3} \mathrm{sgn}\left (b x + a\right ) - A b^{3} e^{3} \mathrm{sgn}\left (b x + a\right )\right )} x^{3} + 18 \,{\left (6 \, B b^{3} d^{2} e \mathrm{sgn}\left (b x + a\right ) - 3 \, B a b^{2} d e^{2} \mathrm{sgn}\left (b x + a\right ) - A b^{3} d e^{2} \mathrm{sgn}\left (b x + a\right ) - B a^{2} b e^{3} \mathrm{sgn}\left (b x + a\right ) - A a b^{2} e^{3} \mathrm{sgn}\left (b x + a\right )\right )} x^{2} + 4 \,{\left (22 \, B b^{3} d^{3} \mathrm{sgn}\left (b x + a\right ) - 9 \, B a b^{2} d^{2} e \mathrm{sgn}\left (b x + a\right ) - 3 \, A b^{3} d^{2} e \mathrm{sgn}\left (b x + a\right ) - 3 \, B a^{2} b d e^{2} \mathrm{sgn}\left (b x + a\right ) - 3 \, A a b^{2} d e^{2} \mathrm{sgn}\left (b x + a\right ) - B a^{3} e^{3} \mathrm{sgn}\left (b x + a\right ) - 3 \, A a^{2} b e^{3} \mathrm{sgn}\left (b x + a\right )\right )} x +{\left (25 \, B b^{3} d^{4} \mathrm{sgn}\left (b x + a\right ) - 9 \, B a b^{2} d^{3} e \mathrm{sgn}\left (b x + a\right ) - 3 \, A b^{3} d^{3} e \mathrm{sgn}\left (b x + a\right ) - 3 \, B a^{2} b d^{2} e^{2} \mathrm{sgn}\left (b x + a\right ) - 3 \, A a b^{2} d^{2} e^{2} \mathrm{sgn}\left (b x + a\right ) - B a^{3} d e^{3} \mathrm{sgn}\left (b x + a\right ) - 3 \, A a^{2} b d e^{3} \mathrm{sgn}\left (b x + a\right ) - 3 \, A a^{3} e^{4} \mathrm{sgn}\left (b x + a\right )\right )} e^{\left (-1\right )}\right )} e^{\left (-4\right )}}{12 \,{\left (x e + d\right )}^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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